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Acceleration





For everyone who reckons increasing BHP will increase acceleration - wrong!!! You need to increase Torque to notice quicker 0-60/0-100 and in gear times - all BHP increases do is give a higher top speed but to increase a top speed by say 10 miles per hour over standard requires a hell of a big increase in BHP - so those who reckon an exhaust system, chip and filter increase a 0-60 dash by a second are sorely deluded............... Increase torque and reap the results and BTW increasing BHP does not automatically increase torque...........discuss
 


Yawn.......wouldnt you rather discuss your 68mph in 2nd cup, and the benefits of the chip you seem to love?
 


Thats all well and good, but its not some amazing discovery nor a blanket rule.

A 16v/VTS etc are low on torque, but arent exactly slow...

Theres some more explaining to be done.
 


Power to weight ratio is more key IMO

Like Ben H said, 16v/VTS dont have much torque and are still quick and thats down to weight.

So I think the comment was a bit generalised. Yes torque is very important, being the ability to produce the power (turning force) but that doesnt help you all the way. You need a good combination.
 


The Willy doesnt develop much more torque than the 16v, something like 6% more (119lb/ft plays 129lb/ft).

But it develops 85% of that torque at a measly 2500rpm, whereas the 16v gets it at over 4000rpm.

So the spread of torque is important too.
 
  Audi S3


ok quick q torque is measured in 2 ways

N/M and lb/ft right

which one give a bigger reading (just to clear summit up in my head)

Matt
 


Quote: Originally posted by weight on 16 April 2003


Torque wins races!

BHP sells cars!

easy.
Oh thats so much bull sh*t, my pal has a chipped Ibiza Cupra 195 hp 240 lbft weighs 1115 kg now if torque wins races why can I pull away from him all the way? Because it makes 240 lb ft on a very narrow power band (like a TDI) where the 172 makes a nice fat spread of torque over a longer band.
 


No you said torque wins races but a car with lots of torque like a TDI aint going to touch a 172 for example cause of the way it makes its torque.
 


i think your all generalising too much.

A cup that makes 200nm and one that has the same peak power but 220nm and peaks its toque earlier will win.....simple.

An offroad vehicle can have as little as 68bhp (the old skool landcruisers) but heaps of torque. Its all relative my friends.
 


I bet the Ibiza doesnt have to think what gear he needs to be in as much though. If you were both in 3rd at 2000rpm, hed pull from you no problem. But if you were both driving them how they need to be driven to get best performance, youll win because the Cup is lighter and has a better power to weight

Edit: Sorry, I was thinking it was a TDi.....thats what I was talking about....TDis having oodles of torque at low down usable revs
 


Quote: Originally posted by mikeherts on 16 April 2003


I bet the Ibiza doesnt have to think what gear he needs to be in as much though. If you were both in 3rd at 2000rpm, hed pull from you no problem. But if you were both driving them how they need to be driven to get best performance, youll win JavaScript must be enabled on your web browser for you to post a message in the forum!because the Cup is lighter and has a better power to weight

Edit: Sorry, I was thinking it was a TDi.....thats what I was talking about....TDis having oodles of torque at low down usable revs





You seen some of the ingear stats for the Cup/172 it wouldnt get disgraced @ all! Anyway if im racing i aint going to use 3rd so that argument dont really work with me.
 


Its not an "argument" Neil. Its a very valid point...........do you drive around the whole time with your revs poised in the upper rev range where we all know the RenaultSport 2.0 16v gives out most of its power. I certainly dont. If something decided it wanted to race, Id often have to drop a gear, whereas a car with lots of torque low down (i.e. turbos) can often get away with being one notch up and still pull hard.

Im not saying the Cup would be embarrassed at all, just that the engine is revvy and has to be kept on boil more.
 


you say your car is quicker!

BUT HOLD ON IT DEVELOPES LESS POWER:confused:

so what could it be that makes you win the race??

YOUR TORQUE CURVE COMPARED TO HIS??:)
 


Quote: Originally posted by mikeherts on 16 April 2003


Its not an "argument" Neil. Its a very valid point...........do you drive around the whole time with your revs poised in the upper rev range where we all know the RenaultSport 2.0 16v gives out most of its power. I certainly dont. If something decided it wanted to race, Id often have to drop a gear, whereas a car with lots of torque low down (i.e. turbos) can often get away with being one notch up and still pull hard.

Im not saying the Cup would be embarrassed at all, just that the engine is revvy and has to be kept on boil more.





Didnt mean argument in that sense m8, is torque a bi product of hp or the other way round?
 


um, my 100cc kart can out accelerate most rd cars, and the torque curve on that is non existent. It dont work till your up at about 9000rpm........

There are far too many variables to actually SAY this and that......
 


Torque is in basic terms, the ability to produce your power - i.e. the turning force. Not sure which way round it would be though!
 


BHP is the work done (remember science class lol) and torque is the actual power output of an engine.

1bhp = 33,000ft.lbs/min
 


Yeah i did read a website - its better than pety arguing between people who dont have a clue..........;)
Id rather discover facts and pass them on to those who are interested!

Who knows where BHP and Torque are exactly the same figure?

Originally horsepower was considered to be one unit when a horse could raise, by single pulley, one hundred fifty pounds at a rate of 2.5 mph, or 550 foot pounds per second.

This in energy terms turns out to be 746NM per second, or in electrical terms is 746Watts.


Mechanical horsepower = torque (in foot-pounds) * RPM / 5252.

The torque output of an internal combustion engine varies with RPM, being zero at very low RPM, rising to a peak level, then falling to zero again at the engines maximum speed. Some engines produce high torque only in a narrow band of output speeds, others have a wider power band. Maximum horsepower is determined by looking at the point on the speed-torque chart where torque*rpm is greatest. This gives you an idea of the maximum power the engine can produce, but to get the full picture you need to look at the power/speed curve to see how the engine will behave in reality.



There is no such thing as a "torque" engine. Any engine that produces 300 ft-lbf of torque at 3000 rpm has 171 hp at that speed. Regardless of its stroke, bore, displacement, supercharger, etc. Also, any engine that makes 300 ft-lbf of torque at 5000 rpm will produce 286 hp. This is due to the simple relationship between power and torque:

power = (torque * rpm) / 5250

where power is in horsepower, and torque is in ft-lbf. Also note - at 5250 rpm, hp is equal to torque numerically.

Racing engines are designed to produce a lot of torque at high engine speeds, because this will lead to increased horsepower. This engine can then be geared for whatever range of speeds it will normally be driven in.

The biggest problem with production cars is they spend the vast majority of their time under 4000 rpm, and larger engines (like my Mustangs 4.6 l) spend most of their time below 2500 rpm. Another related problem is that due to the direct relationship between power and rpm, the power produced at these low engine speeds is low. So to get more power at common driving engine speeds, you must therefore increase the torque at these lower engine speeds.

Engine power increases with rpm because power is a function of time. torque, on the other hand, is relative to the force exerted on the piston by the expanding gases in the cylinder. If you had perfect, equal cylinder filling on each stroke, then this force would be proportional to the bore, or displacement of the cylinder, and this force would be equal per stroke regardless of rpm. You can think of power as being determined therefore by how often this cylinder fills and fires in a given amount of time. One of the reasons two-stroke engines produce so much more power than a comparable four-stroke engine - although it has a poorer volumetric efficiency (the efficiency of filling the cylinder with fuel-air mixture), it fires twice as many times in the same amount of time.

So to increase low-end torque, we must actually also see what increases low-end power. And vice-versa. Engine torque will derive from the pressure exerted on the top of the piston by the exhaust gases. The average pressure exerted on the piston through the length of the stroke is known as the mean effective pressure (mep), and is given in terms of psi. Another measure, imep or indicated mean effective pressure, is determined by using some fancy equipment to actually measure on a running engine what the pressure is. Engineers commonly use mep as an indication of power plant performance in internal combustion (IC) engines.

Because its pretty hard to measure the imep, another measure, brake mean effective pressure, or bmep, is often calculated in its stead. This equation is:

bmep = (hp * 33,000) / (Length * Area * N)

where hp is power in horsepower, Length is the length of the stroke in ft, Area is the piston top surface area in square inches, and N is the power strokes per minute (or rpm / 2 for a four-stroke engine).

Now, what are the things that affect this bmep? Well, the first is volumetric efficiency. This of course is the efficiency of filling the displacement of the engine with fuel and air mixture on each stroke. You could also look at it this way - if a cylinder only fills with 85% efficiency on each stroke, this is similar to reducing your engine displacement (size) by 15%. Due to frictional losses, valve overlap, etc. this will not ever be 100% in a naturally aspirated engine. In fact, this efficiency falls off steadily as engine speed increases. One way to get back these losses is to use a turbo or supercharger, which will compress air into the cylinder, and thus give a volumetric efficiency relative to a naturally aspirated engine of more than 100% (but its not actually more than 100%, because you cant look at it that way…)

What else increases volumetric efficiency? Well, tuning of the exhaust and intake runners will achieve some level of "pressure wave supercharging", to help move the intake gases in and the exhaust gases out. A lower restriction air cleaner, fuel injection system, intake manifold, larger and more valves, etc. will also increase airflow into the engine. Likewise, lower restriction exhaust, removal of the catalyst, larger and more exhaust valves, etc. will allow the exhaust gases to flow out of the cylinder more easily. Also note that for both the intake and exhaust cycles, the valve timing and lift are also key to not only achieving greater volumetric efficiency, but also to tuning where the maximum possible flow through the valves will occur.

And when youve looked at what you can do with respect to volumetric efficiency, there is now friction horsepower loss to contend with. This tends to increase as a function of the square of the rpm of the engine, and can be very substantial at high speeds. One reference I have here gives the friction horsepower of a "stock" 350 Chevy as being 12 hp at 2000 rpm, 25 hp at 3000 rpm, 47 hp at 4000 rpm, 72 hp at 5000 rpm, and 110 hp at 6000 rpm. This friction loss can be reduced by careful engine building and lower-friction bearings and components, and by synthetic oils. But the trend of increase remains the same shape.

Now lets look at bore and stroke. Increasing the stroke of an engine by increasing the crankshaft throw not only increases the displacement of the engine, but also increases the mechanical advantage on the crankshaft. So increasing the stroke increases the torque both from increased displacement and from greater mechanical advantage. Thus, even for two engines of the same displacement, the one with the greater stroke should have the greater torque. However, there are some other things to consider here:

1) As stroke length increases, thus does the piston speed at the same rpm, and therefore the frictional power loss will increase as well.

2) As this piston speed increases, the volumetric efficiency will fall off as well. A larger bore engine will also allow for larger and/or more valves, with less shrouding needed. Thus, if the two engines have the same displacement, then the shorter stroke one will have the greater volumetric efficiency.

3) You also have to consider inertia effects of the longer connecting rod, and increased side-forces on the rings and piston due to the increased rod angularity with respect to the bore centerline.

Of course, there are those that will argue that a larger bore engine may result in an increased chance of detonation at high compression ratios than a smaller bore engine, due to an increased distance that the flame front must travel across. But this will vary greatly due to combustion chamber design, and I dont know if it can be analyzed so generally. Overall, many claim that the small bore/long stroke engines are much better suited to the higher compression ratios, and if in our example of the two equal sized engines we also have a higher compression ratio than the larger bore one, then the larger stroke engine will see even more torque improvement.

Another theory related to this is the "long rod" theory, which says that the longer the connecting rod is, the more time or "dwell" the piston will have at top dead center (TDC). And therefore, there will be more time allowed for the gases to burn completely at the highest engine pressure. Thus, you will get even more force out of each firing with the same amount of fuel as the rod descends through its stroke. However, what really happens is that the long rod has a very small mechanical advantage due to its angularity at these high pressures, and thus this effect is negated. A short rod, attached to a crankshaft with a long throw, will move towards a higher angularity faster than a long rod with a short crank throw.

Another advantage of a long throw/short rod engine is that cam timing is not nearly so important as in a short throw/long rod engine. This is due to the fact that the piston spends less time at or near TDC, and thus allows for an earlier valve lift start and longer duration. Also, the exhaust valve can stay open longer as the piston ascends, increasing the amount of exhaust gas that is pushed out of the cylinder, and thus increasing the volumetric efficiency.

And so on, and so on. I am tired of typing now. Hope someones learnt something.
 
  Nissan R35 GT-R


The thing is that power cannot exist without torque in an engine.

If you can get the torque to never drop off no matter how far you rev, you will make more and more power the more you rev. So you could have 150 lb/ft of torque and make 1000bhp. You would have to rev to around 38,000 rpm though!

If the torque stayed at 150 lb/ft @7250rpm on a 172 it would be making 207 bhp! BHP simply means how fast will the car go, and the torque curve defines how fast it will get there.

If two cars have the same amount of power, one weights 1000kg and the other weights 2000kg they will both have the same top speed (on saying that the gear ratios are the same and they are not too strong for the latter car).
 


Quote: copied from someone else by CUPSIZE? on 17 April 2003


where power is in horsepower, and torque is in ft-lbf. Also note - at 5250 rpm, hp is equal to torque numerically.
Interesting that. Just looked at the graph from the RR day at Nobles. Torque and BHP cross at 5400rpm.
 


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