Seconds=Car lengths....

[Dubai182]

Hi Guys/Girls,

I was wondering if you could clear something up for me..

Lets say my RS does 0-60 in 6.6 seconds and car 'b' does it in 8.0 seconds. From a standing start what does 1.4 seconds look like in terms of car lengths?
Same goes for 1,2,3,4 second time gaps? 1 second=2 car lengths??

 

[blaze]

at 100 mph it's 54 metres IIRC

Blaze

 

[blink172]

The train left the station at 9am and lilly was wearing yellow sandles. lol

About 5?

 

[benhwolves]

doesnt work like that! an 8 seconder and 6.5 - nothing in it as you forget that while you're doing 60 the 8 seconder is prob doing 55 and still sat on your ass, you'd be pulling a slight gap

 

[LegoHead]

faster car will be 21.9m ahead.

 

[E-ray_172]

yeh but u also have to remember the car A and car B May have different accelaration under 60mph.
so if lets say Car A- does 60 in 6.6
and Car B- does 8.0 ok BUT...

Car B does 50mph in 5.9
and car A does 50 mph in 6.3

it shows that car B was in fact ahead til about 50mph where it died of buff and Car A took him, so in term of car lenghts it can vary alot depening on speeds below.

i think i got the right idea anyway lol.

 

[Dubai182]

^^^ I was thinking along those lines mate. I'm curious as i had a quick blast off the lights against a car that i looked up took 8 secs to reach 60mph,i only had him by around 1/2 car lengths.

Good posts boys!!

 

[chiefsilverback]

Am I right in thinking that both cars will travel the same distance getting to 60, but the faster car will have had an extra 1.5 seconds at 60 which equates to 40m!?!?!?

 

[BigBarry172]

Have to agree with E-rays 0-50mph comment.

My 172 pull's away from 0-10mph quite sluggishly due to the inertia of my 18's, but after that it picks up like a mo-fo to 60. I reckon quite a few lesser powered / spec'd cars can pull away from a stand still quicker than me..... but they would soon be rinsed.........!!!!

Haha! love it!!!

 

[kully]

The train left the station at 9am and lilly was wearing yellow sandles. lol

About 5?

pmsl:star:

 

[LegoHead]

faster car will be 21.9m ahead.

thats assuming uniform acceleration.

If you have the velocity-time function for each one, integrate them for 0 to 6.6 seconds and find the difference.

 

[MarkCup]

Trying to keep it simple here...

Assume both cars accelerate at the same uniform rate
Assume that as car A (6.5s) reaches 60mph, car B is doing 55mph (8.0s)
Speed differential after 6.5s is therefore 5mph, so average speed differential over 6.5s would be 2.5mph

How far do you travel in 6.5s if you're doing 2.5mph? 1 car length...maybe 1.5? So I'd say there's bugger all in it.

Does all this make any sense at all (it does to me)?

Just worked it out - 2.5 mph, for 6.5s = approx 6 metres, or 1.5 car lengths.

 

[Dave H]

3/4 of a mile

 

[Tyson-182]

Y x Z (A~B) + 8 / 6.5 = Y+B x ZA - [Terminal speed] + 60 (X~Y) @ Cliosport.net = 2.5...Okay?

I have no idea really, but i would like to know the answer if someone has it?

Tyson.

 

[recaro182]

Who cares if its 1 car length or 10, winning is winning

 

[chiefsilverback]

Am I right in thinking that both cars will travel the same distance getting to 60, but the faster car will have had an extra 1.5 seconds at 60 which equates to 40m!?!?!?

I'm not right, using the example of a Porsche and a Skoda starting from the same point:

the Porsche would cover less distance in achieving 60mph because of the greater acceleration.

Distance is in metres, or miles
Velocity (or speed) is in metres per second
Acceleration (rate of change of velocity) is in metres per second, per second

Faster acceleration = Quicker change in speed => less time required to achieve it

It's sometimes useful having a mathmetician for a brother!!

 

[blink172]

This is going to be like that f**king plane thread isnt it?

 

[al]

Ouch, my brain hurts now after reading that!

 

[b3ns0n]

From my calculations, assuming constant acceleration (unrealistic model, but that's all that can be done with this info) by the time car A hits 60mph it has covered 89m, at which time car B will have covered 73.5m and be doing roughly 50mph.

Hope that helps.

 

[Graham22b]

From my calculations, assuming constant acceleration (unrealistic model, but that's all that can be done with this info) by the time car A hits 60mph it has covered 89m, at which time car B will have covered 73.5m and be doing roughly 50mph.

Hope that helps.

Yeh he's right, assuming uniform acceleration your car goes 88m whereas other car goes 72.6m (rounding answers)

In real life of course acceleration is never uniform so to get realistic answer you have to use calculus.

As people said the real answer depends on a huge amount of variables. Power bands of cars in question, ability to get traction down, torque in lower gears etc as 0-60 is just a best case scenario stat. Of course the biggest variable of all is the driver!

 

[gazcaddy]

Its very complicated this and thats why it is possible car A could be 1 car length etc in front of car B even though they both have exaclty the same 0-60 time. So its also possible that a car with a faster 0-60 time could be a car length behind a car with a slower 0-60 time.

A better measure of performance is the time it takes a car to cover a certain distance

 

[Dave H]

Buy a longer car

 

[Dubai182]

Good work soldiers,so roughly 1.5 car lengths explains why i was up roughly 1/2 car lengths,LMAO.
Can get very techincal can't it?

 

[Tyson-182]

Madness!

Tyson.