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Well it don't go to bad now does it and that's on 17s !!!!!
And that means that it wouldn't be better on 15's does it?
You're wrong. I'm not going to post the formula again as it's very long and I can be arsed. But, lighter wheels are better. FACT.
And I'm guessing that, from your answer, you don't understand the physics, and are just spouting crap which you don't understand.
You're wrong. I'm not going to post the formula again as it's very long and I can be arsed. But, lighter wheels are better. FACT.
And I'm guessing that, from your answer, you don't understand the physics, and are just spouting crap which you don't understand.
The laws of physics rule here. Energy is needed to bring the wheel/tire mass up to speed (mph) and to spin it to the related rpm. Consider a lighter tire/wheel combo:
m = mass reduction
I = inertia reduction
w = rotational speed
v = car speed
r = tire radius
E = total energy saved by mass reduction "m"
^2 = squared
E = 1/2 m v^2 + 1/2 I w^2
E = E(speed) + E(rotation)
Rotary Inertia is the sum of each bit of mass times it's radius squared. If all the mass reduction is at the tire OD (the theoretical but not practical limit), the inertia reduction is the maximum possible value:
I = r^2 m
The relation between car speed and tire rpm:
v = r w
Combine 3 equations above:
E = 1/2 m v^2 + 1/2 (r^2 m) (v/r)^2
E = 1/2 m v^2 + 1/2 (m) (v)^2
E = 2 x E(speed) ... the 2X limit
So if you drop 10 lbs per corner, the net total weight savings is 4 x 17 = 68 lbs. For a 3700 lb car and driver, that's only a 1.8% change.
The main benefit of reducing wheel/tire or any unsprung weight is handling and comfort, by increasing the tires ability to keep good contact with the road. Total unsprung weight might be 80 lbs per corner, and 10 lbs would be a 13% change ... very significant.
This is for linear acceleration, And assuming equal weight distribution across the wheel. The true equation is a horribly complicated logarithmic job. But the point is the same.
The difference is greater the more power you have too.
m = mass reduction
I = inertia reduction
w = rotational speed
v = car speed
r = tire radius
E = total energy saved by mass reduction "m"
^2 = squared
E = 1/2 m v^2 + 1/2 I w^2
E = E(speed) + E(rotation)
Rotary Inertia is the sum of each bit of mass times it's radius squared. If all the mass reduction is at the tire OD (the theoretical but not practical limit), the inertia reduction is the maximum possible value:
I = r^2 m
The relation between car speed and tire rpm:
v = r w
Combine 3 equations above:
E = 1/2 m v^2 + 1/2 (r^2 m) (v/r)^2
E = 1/2 m v^2 + 1/2 (m) (v)^2
E = 2 x E(speed) ... the 2X limit
So if you drop 10 lbs per corner, the net total weight savings is 4 x 17 = 68 lbs. For a 3700 lb car and driver, that's only a 1.8% change.
The main benefit of reducing wheel/tire or any unsprung weight is handling and comfort, by increasing the tires ability to keep good contact with the road. Total unsprung weight might be 80 lbs per corner, and 10 lbs would be a 13% change ... very significant.
This is for linear acceleration, And assuming equal weight distribution across the wheel. The true equation is a horribly complicated logarithmic job. But the point is the same.
The difference is greater the more power you have too.
powerstation RR it made 268.8 hp
I think the figures and videos don't do them justice.
Clio T 314hp c43 AMG
Welcome to the debate that started and finished in January lol, looks like it goes well!
Lol, i know. I just copied and pasted my reply to that thread into this one
It's one of those things that comes up all the time.
Sweet Jesus. Who wrote that reply?
''AFAIK'', it would appear that you don't 'know' very far.
How would the driver possibly give accurate feedback to the engineers if he doesn't understand the physics?
£5600 and it's yours
I'm wrong! lol...
Jack i've raced since i was 7yrs old, i've got a fairly good understanding of chassis dynamics and track setups! (or at least the racing driver version as Fred would say)
When i say 17's feel better then 15's and 19's feel better than 18's, i wasn't lying, nor was that up for debate. I'M TELLING YOU!
When you've put down the text books let me know!
Correct. But he is insinuating thats smaller wheels are better fullstop. I.e GT2 cars should run smaller, lighter wheels?
In your opinion 17's look crap
In your option 15's are better
In your option 15's handle better
As i have said above, i'm sure there is truth in the Physics, but sometimes driver style & feel is far more important.
Take Knockhill for example:
The Clio was noticeable more balanced on the 17's than it was on the 15's. Even the Radicals went up a rim size for balance.
Karts too, we ran a 6inch rim instead of 5, the turn in was lazy (Suited me better) but far easier to drive, and drive consistently.
Like I’ve said, what works for you may not apply to everyone else.
Closing statement, I’d imagine the majority of owners use their cars daily, therefore the physics of going to Asda via the pub is rather negated; don't you think!
Fair point mate, I'm not suggesting that the physics is the be all and end all of car/driver performance.... but it is the easiest way to get people that don't really understand what they're talking about to see your point / understand the idea.
Obviously you do know what you're talking about, so my comments weren't aimed at you.
90% of the arguments on here must be caused by people misreading/misunderstanding things....
I'll take you out in mine on 17s then tell me it don't handle!!!
Get it set up right then!!!
90% of arguements in life must be caused by people misreading/misunderstanding things...
The 19's on the Z4 are possibly the most uncomfortable things i've ever driven on, coupled with the fact they are a 30profile and over £300 a corner. The ultimate grip however is vastly better than the 18's...But again on the wrong surface they tramline and pull you about!
I often relate back to my Willy, pin sharp turn in on the wee 15's...I hated it!
Clio 172 RS2
16" ftw! ! !
So there you have it!
F1 = 13" wheels as per rules governing...
Article 12.4.2 Of the F1 Technical regulations states that the maximum diameter of a wheel must be less than 660mm with dry tyres and 670mm with wets.
Article 12.4.4 States that the wheel bead diameter must be between 328mm and 332mm.
So there you have it!
F1 = 13" wheels as per rules governing...
Article 12.4.2 Of the F1 Technical regulations states that the maximum diameter of a wheel must be less than 660mm with dry tyres and 670mm with wets.
Article 12.4.4 States that the wheel bead diameter must be between 328mm and 332mm.
